00:01
In this problem the blades of a wind turbine are 30 meter in length and rotate at maximum rotation rate of 20 revolution per minute.
00:10
If the blades are 6000 kilogram each and the rotor assembly has three blades we have to calculate the angular momentum of the turbine at this rotation rate.
00:23
So each of the blades are like rods moving about their ends.
00:32
So moment of inertia of a rod about its end is ml square upon 3.
00:39
M is the mass and l is the length of the rod.
00:43
So total moment of inertia will be equal to 3 times moment of inertia of one rod.
00:54
This is ml square.
00:55
This is the total moment of inertia and the rotation rate is 20 revolution per minute.
01:10
So to convert this into radian per second we multiply by 2 pi because one revolution is 2 pi radian and one minute is 60 seconds.
01:21
So we divide by 60 seconds.
01:24
So the angular velocity in radian per second is 2 .09 radian per second.
01:32
So the angular momentum is equal to the total moment of inertia times angular velocity.
01:45
Mass is 6000 kilogram and length is 30 meters.
01:55
Omega is 2 .09...