The boiling point of propanol is $97^{\circ} \mathrm{C}(370 \mathrm{~K})$, much higher than that of either ethanethiol $\left(37^{\circ} \mathrm{C} / 310 \mathrm{~K}\right)$ or chloroethane $\left(13^{\circ} \mathrm{C} / 286 \mathrm{~K}\right)$, even though all three compounds have similar molecular masses. Explain.