Question
The bond dissociation energy of $\mathrm{B}-\mathrm{F}$ in $\mathrm{BF}_{3}$ is $646 \mathrm{kJmol}^{-1}$ whereas that of $\mathrm{C}-\mathrm{F}$ in $\mathrm{CF}_{4}$ is $515 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The correct reason for higher B-F bond dissociation energy as compared to that of C-F is: $\quad$(a) smaller size of $\mathrm{B}$ atom as compared to that of $\mathrm{C}$ atom $\square$(b) stronger $\sigma$ bond between $B$ and $F i n B F_{3}$ as compared to that between $\mathrm{C}$ and $\mathrm{F}$ in $\mathrm{CF}_{4}$ $\square$(c) significant $p \pi-p \pi$ interaction between $\mathrm{B}$ and $\mathrm{F}$ in $\mathrm{BF}_{3}$ whereas there is no possibility of such interaction between $\mathrm{C}$ and $\mathrm{F}$ in $\mathrm{CF}_{4}$ $\square$(d) lower degree of $p \pi-p \pi$ interaction between $\mathrm{B}$ and $\mathrm{F}$ in $\mathrm{BF}_{3}$ than that between $\mathrm{C}$ and $\mathrm{F}$ in $\mathrm{CF}_{4}$
Step 1
In $\mathrm{BF}_{3}$, Boron has one vacant orbital, whereas in $\mathrm{CF}_{4}$, Carbon does not have any vacant orbital. Show more…
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The bond dissociation energy of $\mathrm{B}-\mathrm{F}$ in $\mathrm{BF}_{3}$ is 646 $\mathrm{kJ} \mathrm{mol}^{-1}$ whereas that of $\mathrm{C}-\mathrm{F}$ in $\mathrm{CF}_{4}$ is $515 \mathrm{~kJ} \mathrm{~mol}^{-1} .$ The correct reason for higher B - F bond dissociation energy as compared to that of $\mathrm{C}-\mathrm{F}$ is: (a) stronger bond between $\mathrm{B}$ and $\mathrm{F}$ in $\mathrm{BF}_{3}$ as compared to that between $\mathrm{C}$ and $\mathrm{F}$ is $\mathrm{CF}_{4}$ (b) significant $\mathrm{p}$ - p interaction between $\mathrm{B}$ and $\mathrm{F}$ in $\mathrm{BF}_{3}$ whereas there is no possibility of such interaction between $\mathrm{C}$ and $\mathrm{F}$ in $\mathrm{CF}_{4}$ (c) lower degree of $\mathrm{p}-\mathrm{p}$ interaction between $\mathrm{B}$ and $\mathrm{F}$ $\mathrm{BF}_{3}$ than that between $\mathrm{C}$ and $\mathrm{F}$ in $\mathrm{CF}_{4}$ (d) smaller size of $\mathrm{B}$ - atom as compared to that of C- atom
The bond dissociation energy of $\mathrm{B}-\mathrm{F}$ in $\mathrm{BF}_{3}$ is $646 \mathrm{kJmol}^{-1}$ whereas that of $\mathrm{C}-\mathrm{F}$ in $\mathrm{CF}_{4}$ is $515 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The correct reason for higher B-F bond dissociation energy as compared to that of C-F is: $\quad$ |A.I.E.E.E. 2009] (a) smaller size of $\mathrm{B}$ atom as compared to that of $\mathrm{C}$ atom $\square$ (b) stronger $\sigma$ bond between $\mathrm{B}$ and $\mathrm{Fin} \mathrm{BF}_{3}$ as compared to that between $\mathrm{C}$ and $\mathrm{F}$ in $\mathrm{CF}_{4}$ $\square$ (c) significant $p \pi-p \pi$ interaction between $\mathrm{B}$ and $\mathrm{F}$ in $\mathrm{BF}_{3}$ whereas there is no possibility of such. interaction between $C$ and $F$ in $C F_{4}$ $\square$ (d) lower degree of $p \pi-p \pi$ interaction between $\mathrm{B}$ and $\mathrm{F}$ in $\mathrm{BF}_{3}$ than that between $\mathrm{C}$ and $\mathrm{F}$ in $\mathrm{CF}_{4}$ $\square$ which overlaps laterally with a filled $2 p$ orbital of $\mathrm{F}$ forming strong $p \pi-p \pi$ bond. However, in $\mathrm{CF}_{4}$ the $\mathrm{C}$ does not have any vacant $p$ -orbital.]
Without looking at a table of bond dissociation energies, determine which bond in each pair has the higher bond dissociation energy. a. H - Cl or H - Br b. CH$_3$ - OH or CH$_3$ - SH
Understanding Organic Reactions
Bond Dissociation Energy
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