Question
The burning of gasoline in a car releases about $3.0 \times 10^4$ kcal/gal. If a car averages 41 km/gal when driving 110 km/h, which requires 25 hp, what is the efficiency of the engine under those conditions?
Step 1
We know that 1 horsepower is equal to 746 watts. So, the power in watts is given by: \[P = 25 \, \text{hp} \times 746 \, \text{watts/hp} = 1.865 \times 10^4 \, \text{watts}\] Show more…
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The burning of gasoline in a car releases about $3.0 \times 10^{4} \mathrm{kcal} / \mathrm{gal}$ . If a car averages 41 $\mathrm{km} / \mathrm{gal}$ when driving 90 $\mathrm{km} / \mathrm{h}$ , which requires 25 $\mathrm{hp}$ , what is the efficiency of the engine under those conditions?
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