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The capacitor in Figure 23.55(a) is designed to filter low- frequency signals, impeding their transmission between circuits. (a) What capacitance is needed to produce a 100 $\mathrm{k} \Omega$ reactance at a frequency of 120 $\mathrm{Hz}$ ? (b) What would its reactance be at 1.00 $\mathrm{MHZ}$ ? (c) Discuss the implications of your answers to (a) and (b).
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Physics 102 Electricity and Magnetism
Chapter 23
Electromagnetic Induction, AC Circuits, and Electrical Technologies
Electromagnetic Induction
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do we know that the capacitive reactor it's for party would be equaling one over to pi times the frequency times the capacitance solving for the capacitance? This would be equaling 21 over two pi times the frequency times the capacitive reactant Now to solve for the capacitance this would be equaling one over to pi times the frequency of 120 hertz multiplied by 100 kilograms or 100 times 10 to the third arms. And we find that the capacitance is equaling 1.33 times 10 to the negative. Eighth Fareed's This would be our answer for the capacitance. For part A for part B we know that solving for the capacitance react the capacitive reactant ce This would be one over two pi multiplied by the frequency of one megahertz. So one times 10 to the sixth hurts. And then this would be multiplied by the capacitance that we found previously 1.33 times 10 to the negative eighth ferrets. And we find the capacitive reactant ce at one mega hurt or what megahertz would be equal in 12 hums. This would be our answer for part B and for part C. The question is asking us, um, discuss the implications So we can say that from the results are from party to part B, we can say that the capacitor impedes low freak onesies significantly more than high frequencies. Uh, we could say it performs work efficiently as it is designed. So those would be some simple up implications. That is the end of the solution. Thank you. For what?
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