00:01
In this question, we are looking at the decay of carbon 15.
00:07
And by looking at appendix b the table, it actually tells us that carbon 15 decays via beta decay, beta minus to be exact.
00:20
And so a final product should involve a beta minus with an antineutrino.
00:30
Since for every decay involving electrons or beta particles, there's always a neutrino or anti -nutriino.
00:37
To figure out what is the final product, here we can use the conservation of the nucleon number as well as the proton number.
00:52
So on the left side we have total proton number of 6.
00:55
On the right side we should expect it to be 6 as well.
00:59
So the product must have 7, so 7 minus 1 is 6.
01:04
For the nucleon number it remains as 15 since both the beta minus and nucleon nootrino don't contribute any nucleon.
01:11
Numbers.
01:14
Looking up our periodic table, we should find that this nucleate over here is a nitrogen nucleic.
01:24
Now we want to find out what is the energy released for this reaction.
01:30
Do that we need to use the mass defect multiplied by c squared.
01:36
So this is the energy being released...