Problem 10 Easy Difficulty

The Cartesian product $\mathrm{A} \times \mathrm{A}$ has 9 elements among which are found $(-1,0)$ and $(0,1)$. Find the set $A$ and the remaining elements of $A \times A$.

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Algebra

NCERT Class 11 - Math

Chapter 2

Relations and Functions

Section 1

Introduction

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Problem 10

Video Transcript

So here we know that. Yeah. Number of elements in A equal to as and number of elements in B equal to B. Then number of elements E. Crosby equal to sp. So here we can see three times three equal to nine because here given number of elements E. Girls eh equal to nine. So here we get number of elements in a equal to three. Number of elements in B equal to three. Then we get a number of elements In equals b equal to nine. Now, given that all repairs negative one comma zero and zero comma one Are two of the nine elements of across a. So here a cross E equal to a coma. E says that small a element of capital, those -1, Coma zero and one How to be the element of E. As number of elements in A equal to three. So here equal to negative one common seal, coma one and equals E. Equal to negative one coma, negative one, -100 negative one Comb a positive one. See you come a negative one, zero comma zero one common negative one. See you cuomo one one comma zero one coma one. So it is our answer.

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