Question
The centres of the three circles $x^{2}+y^{2}-4 x-6 y-12=0, x^{2}+y^{2}+2 x+4 y-10=0, x^{2}+y^{2}-10 x-16 y-1=0$ are(a) collinear(b) non-collinear(c) collinear and lie on $\mathrm{x}$ -axis(d) collinear and lie on $\mathrm{y}=\mathrm{x}+1$
Step 1
Step 1: The general equation of a circle is given by $x^{2}+y^{2}+2gx+2fy+c=0$, where the center of the circle is at $(-g, -f)$. Show more…
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