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The centripetal acceleration $a$ of an object moving in a circular path is $a=v^{2} / R,$ where $v$ is the velocity of the object and $R$ is the radius of the circle. What is the centripetal acceleration of an object moving at $6 \mathrm{ft} / \mathrm{s}$ in a circular path of radius $4 \mathrm{ft} ?$

Calculus 3

Chapter 29

Partial Derivatives and Double Integrals

Section 1

Functions of Two Variables

Partial Derivatives

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So in this problem, we know that. Ah, object. It's moving along. That's taking a path with the radius are and And the angular velocity is Ah! Ow! Mika Equal to pi over one second. So this is a two pi raid a second. Okay, s so we can determine the central it. Ow! Aah! This is the centripetal Ah, acceleration, which is which has a formula Omega squared Times are Okay, so this gives us full pi squared. Times are so this is the acceleration on this subject.

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