00:01
But a of the given problem, the capacitance is given by c is equal to flon a divided by d.
00:09
So we substitute the value for a, which is by r square, and that is 3 .14 times 10 to the power 6 meter square.
00:20
Then we can find capacitance substituting the area, so 8 .85 times, so this is 1 point, times 10 to the power minus 12, times 3 .14 times 10 to the power 6 divided by distance between the plates which is 3 times 10 to the power 3.
00:41
This gives us 9 .27 times 10 to the power minus 9 ferret.
00:49
Part b of the problem, the voltage difference between a cloud and the ground is the cloud and the ground is q divided by c, 20 couloms divided by 9.
01:02
9 .27 times 10 to the power minus 9 ferrard.
01:06
This gives us a potential difference between the cloud and the ground is 2 .16 times 10 to the power 9 volts.
01:16
Part c of the problem, the electric field flows through the air is given by ea is equal to q divided by slon from the goss's law...