Given curve: $y = a \log(\sec(\frac{x}{a}))$
First, let's find the first derivative, $y'$:
$y' = \frac{d}{dx}(a \log(\sec(\frac{x}{a})))$
Using the chain rule, we get:
$y' = a \cdot \frac{1}{\sec(\frac{x}{a})} \cdot \frac{d}{dx}(\sec(\frac{x}{a}))$
Now, we
Show more…