00:01
Hello everyone, let us to the following question.
00:02
Here we have to find value for v0t.
00:05
We will say that this may also be regarded as an inverting amplifier.
00:12
This may also be regarded as an inverting amplifier.
00:19
This may also be regarded as an inverting amplifier.
00:25
Here we will say that 2 course 4 into 10 to power 40 this can be written as 2 into 0 degree and value of omega can be written as 4 into 10 0 0 0.
00:39
10 nanofarid can be written as here we will say that 10 nanofarid can be written as 1 by j omega c from this we will write j 2 .5 kilo oom so here we will write value for v0 by bs this can be written as minus j j .f by j .i.
01:02
So here we will find the value for j .i.
01:07
Where if we find the value for j .i, this can be written as 50 kilo -on.
01:13
And if we write j -f, this is 100 -kil into we will write minus j...