00:02
First up, we can calculate the inductive time constant of the circuit, tor.
00:08
Tor is simply given by l over r.
00:11
The inductance over the resistance.
00:14
The inductance is 8 times 10 to the minus 3 henries, or 8 millie henries.
00:24
And the resistance is 4 oms.
00:28
This gives a time constant of 2 times 10 to the minus 3.
00:33
Or two milliseconds.
00:38
Next we need to calculate the current at a time of 250 microseconds after the switch is closed.
00:48
We know that e that i is emf over r into one minus e to the minus t over tall and we know the emf to be vols and and the resistance to be 4 oms.
01:13
So suppressing the units multiplied by 1 minus e to the minus 0 .25 to bring that into milliseconds over tall, which is 2 milliseconds...