00:02
For this question, according to kenshoff's loop rule, we have a, b, e, f, a, loop.
00:15
So we have 8i plus we have i -n, you have negative 4, negative i, negative 5, i, we have 0.
00:32
And we have b, c, d, e, b, loop.
00:38
So we have negative 5i, negative i, plus 4 minus 12 plus i2, negative 3, i 2, and we have 0.
00:52
Now from equation 1, we have 8i plus 8i 2, negative i, negative 5 ,000, negative 5, 5i and we have 4 negative 4 so this would be equal to 2 i plus 8 i 2 so we have 4 so we have i 1 plus 4 i 2 which is 2 okay so this is our answer for number 1 now from equation 2 you have negative g i negative 2 i 2 8 so we have 3i positive i 2 should be equal to negative 4 and for this one we will going to get from 1 and 2 so we have 3 i positive 12 i 2 6 so we have 3 i plus i 2 2 2 2 2 2 2 so we have 3 i plus i 2 2 be negative 4 and this would be equal to 11 i2 is which is equal to 10.
02:26
So i 2 will be equal to 10 divided by 11 amp.
02:34
Next one for 3, r3, we get i plus 4 times 10 raised to the power 11, which is equal to 2.
02:51
So i will be equal to 2 minus 40 divided by 11.
02:55
That is equals to negative 18 divided 11 amp, which is equals to i1.
03:04
This is our answer for part 3.
03:08
The negative sign signifies the opposite direction used to assume...