Question
The coefficient of static friction between the flat bed of the truck and the crate it carries is $0.30 .$ Determine the minimum stopping distance $s$ which the truck can have from a speed of $70 \mathrm{km} / \mathrm{h}$ with constant deceleration if the crate is not to slip forward.
Step 1
We do this by multiplying the speed by 1000 to convert kilometers to meters, and then dividing by 3600 to convert hours to seconds. So, the speed of the truck is $70 \times \frac{1000}{3600} = 19.44 \, \text{m/s}$. Show more…
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The coefficient of static friction between the flat bed of the truck and the crate it carries is 0.30. Take mass of the crate is m kg. Determine the minimum stopping distance s which the truck can have from a speed of 70 km/h with constant deceleration if the crate is not to slip forward.
The coefficient of static friction between the 200 -kg crate and the flat bed of the truck is $\mu_{s}=0.3 .$ Determine the shortest time for the truck to reach a speed of $60 \mathrm{km} / \mathrm{h}$ starting from rest with constant acceleration, so that the crate does not slip.
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