Sign up for our free STEM online summer camps starting June 1st!View Summer Courses

Auburn University Main Campus

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
Problem 63
Problem 64
Problem 65
Problem 66
Problem 67
Problem 68
Problem 69
Problem 70
Problem 71
Problem 72
Problem 73
Problem 74
Problem 75
Problem 76
Problem 77
Problem 78
Problem 79
Problem 80
Problem 81
Problem 82
Problem 83
Problem 84
Problem 85
Problem 86
Problem 87
Problem 88
Problem 89
Problem 90
Problem 91
Problem 92
Problem 93
Problem 94
Problem 95
Problem 96
Problem 97
Problem 98
Problem 99
Problem 100
Problem 101
Problem 102
Problem 103
Problem 104
Problem 105
Problem 106
Problem 107
Problem 108
Problem 109
Problem 110
Problem 111
Problem 112
Problem 113
Problem 114
Problem 115
Problem 116

Need more help? Fill out this quick form to get professional live tutoring.

Get live tutoring
Problem 72

The combustion of one mole of liquid octane, $\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{6} \mathrm{CH}_{3}$ produces 5470 $\mathrm{kJ}$ of heat. Calculate how much heat is produced if 1.000 gallon of octane is combusted. See Exercise 3.68 for necessary information about octane.

Answer

$1.27 \times 10^{5} \mathrm{kJ}$

You must be logged in to like a video.

You must be logged in to bookmark a video.

## Discussion

## Video Transcript

So in this problem, we're as that on the compassion off. One mole off liquid oct in ah can produce five, four, seven zero killers Jule off hit. We have to calculate how much it is produced if one gallon off tiny's Col mustard. So first you have to find out the number ofthe malls off ock ten for one gallon, off walked in. And from there we can say that if one more off OCD and can produce this much it, then that moral fork then will produce that much heat. So first we have to convert one gallon, tow the militar, and from there using ah, using the density of Faulkner and we can find out the massive for Clint and from their mess, we can find the number of moles by just dividing the mass by the molar mass Now one gallon off Ogden or wanna get off any substances, Um, through seven eight, five point four million later. Now the density of OCD And is it zero pond seven or three, Grandpa are ml. That means, um, the mass off one gallon Ogden is equal to through seven eight five point four million later times zero point seven or three. Grandpa Ramo, which will give us a hand off two six six, one point one four gram Stockton. So this is the mass ofthe one gallon locked in. Now we have to divide this by the Moler massive Falken to get the number of mall so fucked in. So the number of malls for this much octane ese So six, six, one bland one for gram over the molar mass of oxygen, which is one hundred fourteen point toe trade. Crump, Armel. And this will give us a value off twenty three. Plant three zero mall. I said, this is the number of mole for one getting knocked. And now we have seen that one matloff octane can produce five four seven zero kilo Jule off it, that means twenty three points, three zero more octane will produce five four seven zero killer Jule times. Um, twenty three point three zero. And it could give us a fellow off one point two seven times tenderly bar five killers Soul. So one point two seven times and never fight. Still, a jewel heat will be perused from twenty three point three zero mall and our one gallon off walked in

## Recommended Questions