00:01
All right, so this question asks us to identify the alken that is reacted with bromine to get this 2 -3 -di -bromo -2 methylhexane molecule.
00:13
So our first steps in identifying the hexene or the double -bonded compound would be to draw the product, which is this 2 -3 -di -bromo -2 methyl hexane.
00:25
So let's break that down real quick.
00:27
Hexane, we know it is a six -carbon compound.
00:30
So we can just go ahead and draw a six carbon compound.
00:37
Now we can go ahead and look and we can see that there is a functional group.
00:43
It's a methyl group and it's located on carbon number two.
00:47
So i'll just go ahead and draw that methyl group on carbon number two.
00:52
And then we come over here, we can see that we have two bromine molecules on carbon two and carbon three.
01:00
So again, i'll just come over here, carbon two, we can add a br, and carbon three, we can add a br...