00:01
So in this problem, we are asked to draw the lewis structure for s2n2 first by placing an octet around each of the atoms.
00:17
So in this case, let's go ahead and calculate how many electrons we need to have.
00:25
So we have nitrogen contributing five electron sulfur contributing six.
00:32
It gives you 22 electrons total.
00:37
So here we have four electrons.
00:42
From each of the atoms in the corners.
00:45
So that gives us 16.
00:47
Then we have four bonds.
00:49
So that's 8 and that's 24.
00:51
So we have 24 electrons in this structure.
00:56
So that means we actually end up with too many electrons.
01:01
So we have to do some revision.
01:19
So you can see that if we take away one dose electron from each of the nitrogen and they end up with an odd number of electrons, we can get this structure.
01:28
And if we do that to the sulfur, we also end up with charges as well.
01:33
And then we can also form a double bond between these two atoms.
01:47
So that uses up one of the lone pairs on these atoms.
01:53
And then we have four electrons in this bond.
02:02
So let's determine which one of these is going to minimize formal charges.
02:07
So we know that this one results in an octet around.
02:10
All of the atoms because of the double bond formation.
02:24
I'm also going to go ahead and draw in the lone pairs there so that you can see those.
02:37
Okay, so then let's determine the formal charge.
02:41
So formal charge is valence electron minus non -bonding, minus bonds to the atom.
02:49
So for the sulfur here, we end up getting a positive 2.
02:56
So that's not very favorable.
02:59
And most likely we wouldn't want to pick this structure.
03:10
You can see that formal charges are very high for this one.
03:13
So then let's try this one.
03:19
So you can see formal charge is again very high.
03:22
So this really is not a very stable structure.
03:32
So formal charge goes down when we form the double bond...