00:01
Okay, so we have a compound that's supposed to be the highest energy explosive known as of 1994.
00:09
I can't even pronounce this and it's commonly known as cl20.
00:16
And i've tried to draw it here.
00:20
Then there's an explanation of what's going on.
00:23
So that says there are three possible reactions.
00:35
And i'll write those down in a moment.
00:36
And it says use bond energies to estimate our delta h and b, which releases the largest amount of energy.
01:12
I got to slide something down out of my way.
01:14
Largest amount of energy per kilogram.
01:23
Okay, so there that is.
01:24
And let me begin.
01:28
Okay, for my first reaction, i'm going to switch colors for each one of these reactions.
01:32
Let's start with blue for our first one.
01:35
Our first reaction, we are given c6h6.
01:40
Then 12o12 plus o2.
01:48
This is an s.
01:51
It's a g.
01:52
This sometimes drives me crazy because bond energies usually only work for gs.
01:57
This yields 6co plus 6n2 plus 3h2o plus 3 over 2o2.
02:25
Okay, so reactant bonds.
02:41
I will have in this compound, you can go back and look at this, 3 c -c bonds times 347 kilojoules per mole.
02:55
And i will have 6 ch bonds.
03:03
And that's 413 kilojoules per mole.
03:09
These will all be kilojoules per mole.
03:24
12cn6nn6non6 and double bond o.
03:30
And then this will have 305, 160, 201, and 607.
03:55
Okay, so this is going to, when i add these up, when i multiply, this will be 1041 kilojoules, 2478 kilojoules, 3660 kilojoules, 960.
04:23
1206 and 3642.
04:35
Then next there's 6 c triple bond o times 1072.
04:50
That's 6432.
04:54
I'm going to leave the units up this time because i'm out of room.
05:00
That'll be 6 times 941.
05:10
Then i'll have 6 times oh.
05:16
Is there three ohs? yes.
05:19
It's 467.
05:26
And finally, 3 over 2 o double bond o times 495.
05:38
So that's 742 .5.
05:44
Now when we add these together, we will get 12 ,987 kilojoules minus 15 ,622 .5 kilojoules.
05:59
And this will equal negative 2635 .5 kilojoules.
06:11
There's my first answer.
06:15
Now for my second equation, i'm going to try to do this one a little bit faster...