Question
The concentration of carbon monoxide in an urban apartment is $48 \mu \mathrm{g} / \mathrm{m}^{3}$. What mass of carbon monoxide in grams is present in a room measuring $11.0 \mathrm{ft} \times 11.5 \mathrm{ft} \times 20.5 \mathrm{ft}$ ?
Step 1
The volume of a rectangular room is given by the formula length $\times$ width $\times$ height. So, the volume of the room is $11.0 \, \text{ft} \times 11.5 \, \text{ft} \times 20.5 \, \text{ft} = 2593.25 \, \text{ft}^3$. Show more…
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