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The concentration of commercially available conce…

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Problem 114 Easy Difficulty

The concentration of commercially available concentrated sulfuric acid is 98.0 percent by mass, or
18 $M$. Calculate the density and the molality of the solution.

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Chapter 12

Physical Properties of Solutions

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Video Transcript

Here for the solution, concentration of sulfuric acid is 98 percent by mass. Let the mass of the solution be 100 gram. Thus mass of solvent is equal to mass of solution. Minus mass of s 2 s o 4 point, so the mass of solvent will be 100 minus 98 grams, equal to 2 gram. Now to find the molar mass of s 2 s o 4. We have 21008 gram per mole plus 32.07 gram per mole plus 4106 gram per mole, which is equal to 98.086 gram per mole now to find the moles of solute. We have the formula that moles of s 2 s, o 4, is equal to mass of s. 2 s o 4, divided by molar mass of s. 2 s 4 point here: we substitute the values and we get moles of s. T s. A 4 is equal to 0.99 mole now to calculate the morality of solution. We have morality equal to moles of solute, divided by a mass of solvent, that is g multiplied by 1000 grams. Here we substitute the values and we get 499.5 m. That'S the molarity is equal to 500 m now to find the volume of the solution. We know the formula that equal to moles of solute divide by volume of solution in liter, so we have molarity equal to 0.99 mole divided by volume, la simplifying the formula, and we get the volume l equal to 0.99 mole divided by 18 mole per liter. And we get volume is equal to 0.055 liter now to find the density. We have that 1 liter equal to 1000 ml, so it will be 0.055 l, equal to 1000 ml, divided by liter, multiplied by 0.055 l and we get at 55 ml and the 55 ml contains 98 of s 2 s o 4. This 1 ml must contain 98 gram, divided by 55 ml, multiplied by 1 ml equal to 1.78 gram. Thus, the density will be equal to 1.78 gram per ml, so this is a complete solution step by step. I please go through this.

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Raymond Chang, Kenneth A. Goldsby

Chemistry

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