00:02
Okay, so we're given a problem where we're lifting a person off the ground, 11 meters off the ground, with a mass of 79 kilograms, and the acceleration of 0 .7 meters per second squared.
00:18
Our first task is to find the tension on the rope that is lifting the person, and all we needed to do is balance the equation of tension minus mg is equal to mass times the acceleration.
00:38
Where going up is the positive direction of this problem.
00:47
So we manipulate it and isolate tension, plug in mass, and the acceleration of gravity, and the acceleration of the lift, and we would have a tension of 830 newons of the rope.
01:10
Okay, now let's try to find the work done of that.
01:15
Of that rope itself.
01:19
So all we have to do is just do tension times the distance that it travels, and we would have the work, and we would have a total of 9 ,130 joules of the tension.
01:40
Okay, now let's try to find the work done by the person...