00:01
So this problem, we have a conducting rod sliding on rails and a uniform magnetic field.
00:08
Our goal is going to be to find various things about this setup.
00:12
And on this depiction, we have our magnetic field going into the page.
00:16
Its value is 0 .8 tesla.
00:18
The rod is moving to the right at 7 .5 meters per second.
00:22
The height of this from c to d is 50 centimeters, and i'm denoting the length from d to b as l.
00:32
So the first question is to find the induced emf.
00:38
So we know that the induced emf is going to be given by our change in flux over our change in time.
00:47
We can also write our flux as b times a.
00:54
We don't have to deal with any cosine because the perpendicular of this square region of area and the magnetic field are in the same direction.
01:02
So that cosine is 1.
01:05
Our b field is constant, so we can pull that out.
01:09
So we have b, change in area over change in time.
01:15
Our area, we see that that is our h times our l.
01:19
So we can put in b, change in h, l.
01:26
And here, our height is not changing.
01:30
It's only the length from d to b that's changing.
01:32
So this is b, h, changing length over change in time.
01:39
And that change in length over change in time is just our velocity that we're given.
01:43
So we have all these numbers and we can see what this value is.
01:48
So our b is 0 .8 tesla.
01:53
Our height is 50 centimeters, let that into meters.
01:59
Our change in length over change in time is 7 .5 meters per second.
02:03
And if we plug all of this in, we get 3 volts.
02:14
Now that we have our induced dmf, the question is, what is the direction of the induced current? here we're going to need lenses law.
02:23
So lenses law tells us that the induced magnetic field establishes to mitigate the change in net magnetic flux.
02:49
So we see here, since this bar is moving over to the right, our magnetic flux from this external field into the page is growing...