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The configuration space Mof a particle $p$ moving in a Keplerian force field, such that $$ m \ddot{\vec{r}}=\vec{f}=-\frac{k \vec{r}}{\|\vec{r}\|^3} \quad k \in \boldsymbol{R}_{+} $$ is $\mathrm{R}^3-\{0\}$. Show that Newton's equations of motion confirm PR20; that is more precisely, a second-order differential equation is associated to a vector field $Z$ on TM Show that the vector field $Z$ is not complete.

   The configuration space Mof a particle $p$ moving in a Keplerian force field, such that
$$
m \ddot{\vec{r}}=\vec{f}=-\frac{k \vec{r}}{\|\vec{r}\|^3} \quad k \in \boldsymbol{R}_{+}
$$
is $\mathrm{R}^3-\{0\}$. Show that Newton's equations of motion confirm PR20; that is more precisely, a second-order differential equation is associated to a vector field $Z$ on TM Show that the vector field $Z$ is not complete.
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Differential Geometry with Applications to Mechanics and Physics
Differential Geometry with Applications to Mechanics and Physics
Dean A. Gratton 1st Edition
Chapter 3, Problem 16 ↓

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The force acting on the particle is given by: \[ \vec{f} = -\frac{k \vec{r}}{\|\vec{r}\|^3} \] where \( k \) is a positive constant, and \( \vec{r} \) is the position vector of the particle relative to the origin. Newton's second law states: \[ m \ddot{\vec{r}} =  Show more…

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The configuration space Mof a particle $p$ moving in a Keplerian force field, such that $$ m \ddot{\vec{r}}=\vec{f}=-\frac{k \vec{r}}{\|\vec{r}\|^3} \quad k \in \boldsymbol{R}_{+} $$ is $\mathrm{R}^3-\{0\}$. Show that Newton's equations of motion confirm PR20; that is more precisely, a second-order differential equation is associated to a vector field $Z$ on TM Show that the vector field $Z$ is not complete.
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Key Concepts

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Singularities in Dynamical Systems
Singularities occur in dynamical systems when the forces involved lead to undefined behavior, such as infinite acceleration or collision in finite time. In the Kepler problem, the removal of the origin from the configuration space reflects the presence of a singularity where the force law, inversely proportional to the square of the distance, becomes unbounded. This singular behavior is a key reason for the incompleteness of the vector field associated with the system.
Configuration Space
In mechanics, the configuration space of a system represents all possible positions a particle or collection of particles can attain. For a single particle moving in three-dimensional space, this space is typically ?³; however, if certain positions are forbidden (such as the origin in the Kepler problem due to singularity), those are removed from the space. The configuration space provides the geometric setting in which the dynamics are studied.
Tangent Bundle
The tangent bundle of a manifold, here the configuration space, is the space that contains both the positions and the velocities (or directions) at every point in the configuration space. This bundle is essential for reformulating second-order differential equations as first-order systems by combining the position and velocity information into a single vector field that describes the evolution of the state of the system.
Second-order Differential Equations
Newton's equations of motion are typically second-order differential equations because they involve second derivatives of position (i.e., acceleration). In the context of dynamical systems, these can be reformulated as first-order differential equations on the tangent bundle by introducing the velocity as a new variable, thereby defining a vector field whose integral curves correspond to the solutions of the original equations.
Complete Vector Fields
A vector field is said to be complete if its flow exists for all time, meaning that solutions to the associated differential equations can be extended indefinitely in both forward and backward time. In this context, demonstrating that the vector field is not complete shows that there are solutions which encounter a singularity or blow up in finite time, implying that the dynamics cannot be smoothly continued beyond that point.

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Show that if the net force on a particle forced to move along a one-dimensional straight path depends only on its position, that is F = F(x), then Newton's second law can be solved to find v as a function of x given by: v^2 = v_0^2 + 2/m ∫ F(x')dx'. Comment on the result for the case when F(x) is a constant. Hint: Use the chain rule to prove that v̇ = v dv/dx = 1/2 dv^2/dx. Then re-write Newton's second law in a separated form (using v^2 as a variable) and then integrate.

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