Question
The coordinates of a point on the line $y=2$ from which the tangents drawn to the circle $x^{2}+y^{2}=25$ are perpendicular, are(A) $(\sqrt{46}, 2)$(B) $(-\sqrt{46}, 2)$(C) $(\sqrt{37}, 2)$(D) $(-\sqrt{37}, 2)$
Step 1
The equation of the director circle of the given circle $x^2+y^2=25$ is $x^2+y^2=2r$ where $r$ is the radius of the circle. Show more…
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(a) Find the equations of the tangent lines to the circle $x^{2}+y^{2}=25$ at the points where $x=4$ (b) Find the equations of the normal lines to this circle at the same points. (The normal line is perpendicular to the tangent line at that point.) (c) At what point do the two normal lines intersect?
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A tangent to the circle $x^{2}+y^{2}=1$ through the point $(0,5)$ cuts the circle $x^{2}+y^{2}=4$ at $A$ and $B$. The tangents for the circle $x^{2}+y^{2}=4$ at $A$ and $B$ meet at $C$. The coordinates of $C$ are (A) $\left(\frac{8 \sqrt{6}}{5}, \frac{4}{5}\right)$ (B) $\left(-\frac{8 \sqrt{6}}{5}, \frac{4}{5}\right)$ (C) $\left(\frac{8 \sqrt{6}}{5},-\frac{4}{5}\right)$ (D) $\left(-\frac{8 \sqrt{6}}{5},-\frac{4}{5}\right)$
$x^{2}+y^{2}=25 .$ (a) Determine the equation of the tangent line at each of the following points: ( $\mathrm{i}$ ) (3,4)$;$ (ii) (3,-4)$;$ (b) Find the equation of the tangent line at (3,4) by finding the equation of the line passing through (3,4) which is perpendicular to the (radius) line segment whose end points are (0,0) and (3,4).
An Introduction to Calculus
Implicit Differentiation
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