The correct order regarding the solubility of alkaline carth metal halide in water is
(1) $\mathrm{BeCl}_{2}>\mathrm{MgCl}_{2}>\mathrm{CaCl}_{2}>\mathrm{SrCl}_{2}>\mathrm{BaC} \mathrm{l}_{2}$
(2) $\mathrm{MgCl}_{2}>\mathrm{CaCl}_{2}>\mathrm{BeCl}_{2}>\mathrm{BaCl}_{2}>\mathrm{SrCl}_{2}$
(3) $\mathrm{BaCl}_{2}>\mathrm{MgCl}_{2}>\mathrm{CaCl}_{2}>\mathrm{BeCl}_{2}>\mathrm{SrCl}_{2}$
(4) $\mathrm{CaCl}_{2}>\mathrm{MgCl}_{2}>\mathrm{SrCl}_{2}>\mathrm{BaCl}_{2}>\mathrm{BeCl}_{2}$