00:01
Okay, so here we want to test whether the mean price of diamonds differs from $5 ,600.
00:06
So our re -searched hypothesis here is that mu does not equal $5 ,600.
00:11
So that should always be listed as the alternative hypothesis.
00:14
So we have that our null hypothesis is going to be that mu is equal to $5 ,600.
00:19
And then our alternative hypothesis is going to be that mu is not equal to $5 ,600.
00:24
So then for part b, we want the size of the sample n is, going to be 25.
00:32
So therefore, our degrees of freedom is one less, which is 24.
00:36
So the sample mean price, x bar, is given by the sum of x, which is going to be 1 ,45, 875 divided by n, so divided by 25, which is going to be equal to 5 ,835.
00:54
So then the sample standard deviation is going to be equal to the square root of each x i minus x bar squared divided by n minus one so we get that s is going to be equal to 520 .1142 and then the test statistic is then given as x bar minus mu not and then divided by s divided by the square root of n that's going to give us 2 .26 so the area.
01:28
So the area under the t distribution curve to the right of t equals 2 .26 is the same as the area under the curve to the right of t equals negative 2 .26...