00:01
We're asked to find this dress at point a, b, and d when the couple m is applied to a beam of the cross section shown in a plane, forming an angle, beta.
00:17
Hang on here, a couple m.
00:26
And i believe that my diagram is going to look like this.
00:56
This is d.
00:59
Here is c.
01:00
And we're given that my angle here is beta.
01:23
This is 80 millimeters.
01:27
This is 80 millimeters.
01:32
This is 20 millimeters.
01:38
And this is 30, 30 and 30.
01:49
Okay, i hope that is the right.
01:53
See if i can find that in one more place.
02:06
I hope this is right.
02:11
Sometimes when you don't have the diagrams, i think i've got the right diagram here, but i don't have the book available.
02:20
So i think this is right.
02:43
No.
02:44
Okay, so let me get back to my...
02:47
Okay, so i'm just checking.
03:07
I hope i've got all these correct.
03:11
So let's go ahead and start with moment of the inertia.
03:24
So let's do z and this.
03:39
That might not be the right diagram.
03:42
57 .6 times 10 to the minus third inches cubed, inches to the fourth.
03:56
Hang on.
04:10
And i'm supposed to find points at a, b, a d.
04:18
Well, i'm just going to hope for the best here and hope that i got the right numbers.
04:29
In the y direction, we'll get i 1 over 12 times 1 .2 times 0 .4 cubed.
04:41
And this will equal 6 .40 times 10 to the minus third...