The cross product between two vectors in $\mathbb{R}^3$ is the vector defined by the formula
$$
\mathbf{v} \times \mathbf{w}=\left(\begin{array}{c}
v_2 w_3-v_3 w_2 \\
v_3 w_1-v_1 w_3 \\
v_1 w_2-v_2 w_1
\end{array}\right), \quad \text { where }=\left(\begin{array}{c}
v_1 \\
v_2 \\
v_3
\end{array}\right), \quad \mathbf{w}=\left(\begin{array}{c}
w_1 \\
w_2 \\
w_3
\end{array}\right) .
$$
(a) Show that $\mathbf{u}=\mathbf{v} \times \mathbf{w}$ is orthogonal, under the dot product, to both $\mathbf{v}$ and $\mathbf{w}$.
(b) Show that $\mathbf{v} \times \mathbf{w}=\mathbf{0}$ if and only if $\mathbf{v}$ and $\mathbf{w}$ are parallel. (c) Prove that if $\mathbf{v}, \mathbf{w} \in \mathbb{R}^3$ are orthogonal nonzero vectors, then $\mathbf{u}=\mathbf{v} \times \mathbf{w}, \mathbf{v}, \mathbf{w}$ form an orthogonal basis of $\mathbb{R}^3$.
(d) True or false: If $\mathbf{v}, \mathbf{w} \in \mathbb{R}^3$ are orthogonal unit vectors, then $\mathbf{v}, \mathbf{w}$ and $\mathbf{u}=\mathbf{v} \times \mathbf{w}$ form an orthonormal basis of $\mathbb{R}^3$.