00:01
High, the given problem, refractive index means the index of refraction of the material of eye lens is given as n is equal to 1 .44 and its focal length is f is equal to 8 .0 millimeter or we can say this is 0 .8 centi centimeter.
00:41
Now it is a bifocal lens which is having same radii of curvature on both the sides.
00:53
So if this is the radius of curvature r1 it will be taken as positive and if this is the radius of curvature r2 towards left -hand side that will be taken as negative.
01:06
Means if r1 is positive r then r2 will be negative r so in the first part of the problem using lens makers formula which says 1 by f is equal to n minus 1 into 1 by r 1 minus 1 by r 2 so here this is 1 by 0 .8 for the focal length length is equal to 1 .44 minus 1.
01:54
Bracket 1 by, for r1 this is r and for r2 this is minus r.
02:02
So it comes out to be 0 .444 into 2 by r as here it will become 1 by r plus 1 by r which will come out to be 2 by r.
02:13
So finally on making a cross multiplication we get this 0 .3.
02:21
1 by 0 .8 centimeter is equal to 0 .88 by r so r is the radius of curvature is equal to 0 .8 multiplied by 0 .8 centimeter or it comes out to be 0 .7 .04 centimeters or we can say this is 7 .0 millimeter.
03:03
So for r1, this will be plus 7 .0 millimeter and for r2 it will be minus 7 .0 millimeter.
03:14
The two answers for the first part of this problem...