00:01
High in the given problem initial current the maximum current in a series rl circuit is given as i -0 is equal to 1 .0 then in a time t which is equal to 1 .0 second this current drops.
00:39
To 10 millie ampere.
00:46
Self -inductance of the coil is given as 10 henry and we have to find resistance, the value of resistance.
00:57
So using the equation of current decaying in rl circuit when the switch is opened, that equation is i is equal to i.
01:13
Into e ratio to power minus t by tau.
01:17
Here, this time constant tau is the ratio of l, the self -inductance with r, the resistance.
01:29
So plugging in all known values here, for i, this is 10 millie, or we can say this is 10 into 10 dash par minus 3, sorry, not henry, this is ampier.
01:40
10 into 10.
01:43
0.
01:44
Is equal to i .0, which is 1 .0.
01:52
Into e...