Question
The data in the table give the temperature dependence of the rate constant for the reaction $\mathrm{N}_{2} \mathrm{O}_{5}(\mathrm{g}) \longrightarrow$ $2 \mathrm{NO}_{2}(\mathrm{g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{g}) .$ Plot these data in the appropriate way to derive the activation energy for the reaction.$$\begin{aligned}&\\&\begin{array}{ll}\hline T(\mathrm{K}) & k\left(\mathrm{s}^{-1}\right) \\\hline 338 & 4.87 \times 10^{-3} \\328 & 1.50 \times 10^{-3} \\318 & 4.98 \times 10^{-4} \\308 & 1.35 \times 10^{-4} \\298 & 3.46 \times 10^{-5} \\273 & 7.87 \times 10^{-7} \\\hline\end{array}\end{aligned}$$
Step 1
It is given by: \[ k = A e^{-E_a / (R T)} \] where \( A \) is the pre-exponential factor, \( E_a \) is the activation energy, \( R \) is the gas constant (8.314 J/mol·K), and \( T \) is the temperature in Kelvin. Show more…
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The data in the table give the temperature dependence of the rate constant for the reaction: N2O5 (g) -> 2 NO2(g) + 1/2 O2(g) Plot these data in the appropriate way to derive the activation energy for the reaction. T(K) k(s^-1) 338 4.87 * 10^-3 328 1.50 * 10^-3 318 4.98 * 10^-4 308 1.35 * 10^-4 298 3.46 * 10^-5 273 7.87 * 10^-7 Activation energy: kJ/mol
The data in the table give the temperature dependence of the rate constant for the reaction $\mathrm{N}_{2} \mathrm{O}_{5}(\mathrm{g}) \rightarrow 2 \mathrm{NO}_{2}(\mathrm{g})+1 / 2 \mathrm{O}_{2}(\mathrm{g}) .$ Plot these data in the appropriate way to derive the activation energy for the reaction.
Variation of the rate constant with temperature for the first-order reaction $$ 2 \mathrm{~N}_{2} \mathrm{O}_{5}(g) \longrightarrow 2 \mathrm{~N}_{2} \mathrm{O}_{4}(g)+\mathrm{O}_{2}(g) $$ is given in the following table. Determine graphically the activation energy for the reaction. $$ \begin{array}{cc} \hline T(K) & k\left(\mathrm{~s}^{-1}\right) \\ \hline 298 & 1.74 \times 10^{-5} \\ 308 & 6.61 \times 10^{-5} \\ 318 & 2.51 \times 10^{-4} \\ 328 & 7.59 \times 10^{-4} \\ 338 & 2.40 \times 10^{-3} \\ \hline \end{array} $$
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