00:01
In this question, we know the decomposition of so2 cl2 is first order, and we are provided the rate constant.
00:11
From the rate constant, we can calculate the half -life, knowing for a first -order reaction, t -1 -half is equal to the natural log of 2 divided by the rate constant.
00:20
So natural log of 2, divided by 1 .42 times 10 to the negative 4, 1 over seconds, gives us a half -life of 4 ,880 seconds.
00:32
For part b, it wants to know how long it'll take for the concentration to decrease to 25%.
00:37
First half -life, it decreases to 50%.
00:40
Second half -life, it decreases to 50 % of 50%, which is 25%.
00:47
So two half -lifes have passed to reach 25%.
00:53
So two times the half -life gives us 9 ,760 seconds.
00:58
Then for part c, it wants to know if the initial concentration is one molar...