00:02
The demand and supply functions for three interdependent quantities or commodities are given.
00:08
Where q sub d is quantity demanded, q sub s is quantity supplied, and p is the price.
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We're going to determine the equilibrium price and quantity for this three commodity model.
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It's important to remember that in equilibrium, quantity demanded equals quantity supply.
00:23
So for this first one, actually for all three of them, we can put the quantity demanded equal to the quantity supplied.
00:30
So for this first one, we get 15 minus p sub 1 plus 2 p sub 2 plus p sub 3 equals negative 7 plus p sub 1.
00:42
For the second one, i get 9 plus p sub 1 minus p sub 2 minus p sub 3 equals negative 4 plus 4 p sub 2.
00:51
And for this final one, i get 8 plus 2 p sub 1 minus p sub 2 minus 4 p sub 3 equals negative.
01:01
At 5 plus 2 p sub 3.
01:07
On this first one, we're going to go ahead and solve for p sub 1.
01:10
I'm going to start by adding 7 to both sides, and i'm also going to add p sub 1 to both sides.
01:18
I get 22 plus 2 p sub 2 plus p sub 2.
01:26
I'm going to divide everything by 2, and we get 11 plus p.
01:31
Sub 2, plus 1 half p .7 3 equals 2, equals p sub 2.
01:37
I'm going to go ahead and substitute.
01:40
Sorry, this is p sub 1.
01:41
Substitute p sub 1 in over here.
01:45
I get 9 plus 11 plus p sub 2 plus 1 half p sub 3 minus p sub 3 equals negative 4 plus 4 p sub 2.
01:57
I don't actually need these parentheses since there's nothing in front of it to distribute.
02:02
So i'm going to drop them.
02:03
I'm going to start combining my like terms.
02:06
9 plus 11, we get 20 plus p sub 2 plus 1 half p sub 3 minus p sub 2 equals negative 4 plus 4 p sub 2.
02:18
P sub 2 minus piece of 2 on the left hand side.
02:21
They're going to cancel out.
02:22
This gives me 20 plus 1 half piece of 3 minus p sub 3.
02:28
I have one full piece of 3 here.
02:31
So i'm going to go ahead and change this to 2.
02:34
Over two piece of three, negative four plus four piece of two over here.
02:39
This way i have a common denominator so i can combine that.
02:43
20 minus one half piece of three equals negative four plus four piece of two.
02:50
I'm going to go ahead and add four to both sides.
02:53
I get 24 minus one half piece of three equals four piece of two.
03:02
We're going to go ahead and solve this for piece of two.
03:05
And i'm going to do that by multiplying both sides by one four.
03:07
I'm choosing to multiply by the fraction instead of dividing by four because i have a fraction here to deal with and it's going to make my life easier.
03:17
That's going to cancel out.
03:18
I'm going to be left with p sub two over here.
03:20
One fourth of 24 is six.
03:23
One fourth times negative one half gives me negative one eighth.
03:27
So i get six minus one eighth piece of three equals p sub two.
03:31
I'm going to go down to this bottom equation here and substitute those things in.
03:36
I get 8 plus 2 times 11 plus p sub 2 plus 1 half p sub 3 minus 6 minus 1 8th piece of 3 minus 4 p sub 3 equals negative 5 plus 2 p sub 3.
03:54
I'm going to go ahead and distribute that 2 through and that negative sign through.
03:59
I get 8 plus 22 plus 2 p sub 2 plus p sub 2 plus p sub 3 minus 6.
04:06
Plus one eighth piece of three minus four piece of three equals negative five plus two piece of three.
04:15
Eight plus 22 is 30 minus six.
04:20
So eight plus 22 minus six.
04:24
We get 24.
04:25
I've got two piece of two here.
04:28
I'm going to substitute in this equation here for piece of two, six minus one eighth piece of three.
04:34
And then i have p sub three minus one eighth p sub three minus four...