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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95 Problem 96 Problem 97 Problem 98 Problem 99 Problem 100 Problem 101 Problem 102 Problem 103 Problem 104 Problem 105

Problem 55 Medium Difficulty

The density of a certain gaseous fluoride of phosphorus is 3.93 g/L at STP. Calculate the molar mass of this fluoride and determine its molecular formula.

Answer

$\mathrm{PF}_{3}$

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Aadit S.

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Charotte M.

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Video Transcript

Yeah. All right. So, let's try to find um the formula. And the molar mass of the substance that we know contains phosphorus and floor een. And what we do know is that the density of this substance is 3.93 grams per leader at STP. So STP is standard temperature and pressure 0°C, one atmosphere. Now, this is an important um uh thing to know because there's a shortcut for us to be able to get to our molar mass. Because at STP one mole of any gas doesn't matter what it is. Any gas has a volume Of 22.4 L. So, how are we gonna use that? Well, we know what the definition is of molar mass. It's grams per mole. So, let's use our density. And the fact that 22.4 leaders is one mole at STP to convert two g per mole. So, if we take our 3.93 grams per leaders, that's per one leader. And we multiply that by the fact that we know that there's 22 .4 leaders in every one mole, then that means to our three significant figures that we have because our one leader and our one moller infinite That we have a molar mass of 88.0 g per mole. Mhm. All right. So, we've got molar mass. How are we going to use that to figure out the formula? Well, um what do we know about phosphorous and flooring? Well, the Mass of phosphorus. If you look at your periodic table is 30.97 grams per mole. Floor een Is 19.0 g per mole. So how can we get these two equal 88. Well, um, Let's make this number 23 significant. We know that we're going to have to use only three significant figures with addition and subtraction. So we can say that this is essentially equal to 31.0. And so what we're gonna do with that? Well, if we had one phosphorus at 31, but the total was 88, 88.0 -31.0 is 57 zero. So by using this 31, I've used a phosphorus now Florian is 19 and it turns out that if I use 3 19 that will use all of my mass. So I used a floor een and a floor green and a floor een. So now I've used all 88 g per mole. I've used a phosphorus and three floor Eanes. So we write that is P. F three. So phosphorus try fluoride is the formula of our substance

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