Question
The density of a liquid at $0^{\circ} \mathrm{C}$ is $\rho_{0}$. The density of liquid at $0^{\circ} \mathrm{C}$ is : [volume expansion of liquid is $\gamma$ ](a) $\frac{\rho_{0}}{\left[1+\gamma\left(\theta_{2}-\theta_{1}\right)\right]}$(b) $\rho_{0}\left[1+\gamma\left(\theta_{2}-\theta_{1}\right)\right]$(c) $\rho_{0}\left[1+\gamma \theta_{2}\right]$(d) none of these
Step 1
So, we can write the density at $0^{\circ} \mathrm{C}$ as $\rho_{0} = \frac{m}{V_{0}}$, where $m$ is the mass and $V_{0}$ is the volume at $0^{\circ} \mathrm{C}$. Show more…
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