Question
The density of mercury is $13.6 \mathrm{~g} / \mathrm{mL}$. Calculate approximately the diameter of an atom of mercury assuming that each atom is occupying a cube of edge length equal to the diameter of the mercury atom.
Step 1
We know that 1 mole of mercury (which is approximately 200g) contains $6.023 \times 10^{23}$ atoms (Avogadro's number). Therefore, 1g of mercury contains $\frac{6.023 \times 10^{23}}{200}$ atoms. Show more…
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