Question
The density of osmium (the densest metal) is $22.57 \mathrm{~g} / \mathrm{cm}^{3} .$ If a $1.00-\mathrm{kg}$ rectangular block of osmium has two dimensions of $4.00 \mathrm{~cm} \times 4.00 \mathrm{~cm}$, calculate the third dimension of the block.
Step 1
We are given the mass (1.00 kg) and the density (22.57 g/cm³) of the block. We can use the formula: Density = Mass / Volume First, we need to convert the mass from kg to g: 1.00 kg * 1000 g/kg = 1000 g Now we can rearrange the formula to solve for Show more…
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The density of osmium (the densest metal) is $22.57 \mathrm{~g} / \mathrm{cm}^{3} .$ If $\mathrm{a}$ $1.00-\mathrm{kg}$ rectangular block of osmium has two dimensions of $4.00 \mathrm{~cm} \times 4.00 \mathrm{~cm}$, calculate the third dimension of the block.
Ihe density of osmium (the densest metal) is $22.57 \mathrm{~g} / \mathrm{cm}^{\circ}$. If a .00-kg rectangular block of osmium has two dimensions of $4.00 \mathrm{~cm} \times 4.00 \mathrm{~cm}$, calculate the third dimension of the block.
The density of osmium is 22.57 g/cm3. if a 1.00 kg rectangular block of osmium has two dimensions of 4.00 cm x 4.00 cm, calculate the third dimension of the block.
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