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The dependence of the equilibrium constant of a reaction on temperature is given by the van't Hoff equation:$$\ln K=-\frac{\Delta H^{\circ}}{R T}+C$$where $C$ is a constant. The following table gives the equilibrium constant $\left(K_{P}\right)$ for the reaction at various temperatures$$2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{NO}_{2}(g)$$$$\begin{array}{llllll}K_{p} & 138 & 5.12 & 0.436 & 0.0626 & 0.0130 \\T(\mathrm{K}) & 600 & 700 & 800 & 900 & 1000\end{array}$$

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$$\Delta H^{\circ}=-115 \mathrm{kJ} / \mathrm{mol}$$

Chemistry 102

Chapter 14

Chemical Equilibrium

University of Maryland - University College

Brown University

University of Toronto

Lectures

10:03

In thermodynamics, a state of thermodynamic equilibrium is a state in which a system is in thermal equilibrium with its surroundings. A system in thermodynamic equilibrium is in thermal equilibrium, mechanical equilibrium, electrical equilibrium, and chemical equilibrium. A system is in equilibrium when it is in thermal equilibrium with its surroundings.

00:54

In chemistry, chemical equilibrium (also known as dynamic equilibrium) is a state of chemical stability in which the concentrations of the chemical substances do not change in the course of time due to their reaction with each other in a closed system. Chemical equilibrium is an example of dynamic equilibrium, a thermodynamic concept.

10:55

The dependence of the equi…

03:30

The equilibrium constant $…

So this problem is a little different than other problems leading up to this one in the book. And we want to remember Van Hoffs equation here, and we're working with the following balanced chemical equation and we want to find and full p. But to find empathy in full piece, we'll need to actually doing graph so that we can find the slope of a line given all of our different points. But we can't just graph are KP versus R T Looking at this, you know that we're gonna need the Ln of K, and we're also gonna need one over tea. So we're definitely gonna dio Ellen of K versus one over the temperature. So I'm gonna make a little chart here that is going to take the values in the book and I'm going to for the KP values. I'm going to take the Ln of them. Then for the one over t, we're going to zero point 00167 0.0 143 0.0 1 to 5. 0.0 one of 10 and I'm just gonna add the zero so that we can see, we all have the same six figures. So I highly suggest that you use either a graphing calculator or put these into excel. I put them into a cell personally. So you knew Get the graph itself here is moving town so we can see a little bit better. So I have thesis local line listed here and that this is everything we need to know to find the infill p. So the slope value is a value that comes before the X When you're looking at the form, why equals m X plus B So this right here it's a slope. And we know that this slope is equivalent to negative Well, p over our gas constant. So we found here I'm just going to go ahead and round it to 1.3 times 14th a little bit easier to deal with, and we're gonna know that equals and, you know, p over our gas constant. So since we know are, we can go ahead. I calculate this out and we find that the inflow p equals negative 1.1 five times 10 to the fifth. But this is in jewels per mole because that is what our or ask constant is in our gas constant is 8.314 So we know that if we converts to kill jewels per mole, this is 1 15 killing jewels promote, which is what we usually see and feel P values in.

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