Question
The derivative of $f(x)=1 /\left(1-3 x^{2}\right)$ is given by$$\frac{6 x}{\left(1-3 x^{2}\right)^{2}}$$Do you expect to have difficulties evaluating this function at $x=0.577 ?$ Try it using 3 - and 4 -digit arithmetic with chopping.
Step 1
577$. We substitute $x=0.577$ into the function to get \[f'(0.577) = \frac{6(0.577)}{(1-3(0.577)^2)^2}.\] After calculating, we get $f'(0.577) = 2352911$. Show more…
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