The derivative of $\tan ^{-1}\left(\frac{2 x}{1-x^{2}}\right)$ with respect to $\cos ^{-1} \sqrt{1-x^{2}}$ is
(a) $\frac{\sqrt{1-x^{2}}}{1+x^{2}}$
(b) $\frac{1}{\sqrt{1-x^{2}}}$
(c) $\frac{2}{\sqrt{1-x^{2}}\left(1+x^{2}\right)}$
(d) $\frac{2 \sqrt{1-x^{2}}}{1+x^{2}}$