Problem

The distance between the eyepiece and the objecti…

01:21

Problem 27 Easy Difficulty

The desired overall magnification of a compound microscope is $140 \times .$ The objective alone produces a lateral magnification of $12 \times .$ Determine the required focal length of the eyepiece.

Answer

2.14 \mathrm{cm}

Topics

Electromagnetic Waves

Wave Optics

Book Cover for College Physics 2017

College Physics 2017

Chapter 25

Optical Instruments

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Top Physics 103 Educators

Andy C.

University of Michigan - Ann Arbor

Marshall S.

University of Washington

Zachary M.

Hope College

Aspen F.

University of Sheffield

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Video Transcript

So in this problem, the overall desire magnification off a compound microscope is 140. And I'm using negative Scient because that indicates the images upside down. And the literal magnification of the objective lens is 12. And I'm using natives and for that as well, because the image is inverted. So we know that the overall magnification M is actually the product. So we know overall magnification M is the product of the lateral magnification of the objective and angular, more magnification of the eyepiece. So from here, we can actually write down m e equals em over, and one which is going to be negative 1 40 over negative tools. And this would give me I'm just gonna ride down positive value of that. So it is 1 40/12 All right, now, we also know that M is 25 centimeter over f e. So that means 25 centimeter over Effie is 1 40/12 All right, so from here, you can see that actually, f is going to be 25 times troll over 1 40 and this is going to give me two point once, and David er

Netra S.

University of Wisconsin - Milwaukee

Topics

Electromagnetic Waves

Wave Optics

Book Cover for College Physics 2017

College Physics 2017

Chapter 25

Optical Instruments

Top Physics 103 Educators

Andy C.

University of Michigan - Ann Arbor

Marshall S.

University of Washington

Zachary M.

Hope College

Aspen F.

University of Sheffield