the-detonator-on-a-ride-called-the-detonator-at-worlds-of-fun-in-kansas-city-passengers-accelerate-s

Question

The Detonator On a ride called the Detonator at Worlds of Fun in
Kansas City, passengers accelerate straight downward from rest to
45 $\mathrm{mi} / \mathrm{h}$ in 2.2 seconds. What is the average acceleration of the
passengers on this ride?

Nathan Silvano · Accepted Answer

So in this question we have the passengers over right, accelerating downwards from rests to a velocity to a speed. The finest front of velocity of 45. My owes for our in a time of just 2.2 seconds. And the problem wants to know what is the average acceleration off the off the right, Let&#x27;s see average acceleration. We know that the average acceleration is just the difference. And the loss. It&#x27;s divided by the total time we spent to just fridges velocity. We know that the velocity is just 45 miles Pereira because the initial velocity zero So what is the time? Well, our time right now isn&#x27;t seconds. So we need to change the time for hours. So how do we change the time off seconds from ours? We know that transforming seconds two minutes is just divided by 60 and transforming minutes. Two hours was just dividing by 60. So divided by 60 again, we just I have two divided this 2.2 divided by tree 1006 100. This is going to be something around 6.1111 times 10 to the power off minors. For now, we can calculate it. Our average acceleration the average acceleration is going to be 45 divided by 6.1111 time staying to the power of minus for this power goes up. So we have the average acceleration. Both seven point 36 36 Theiss times 10 to the power of four or right average acceleration plus seven, 3636 My owes for our That&#x27;s the final answer. Thanks for watching.

Nathan Silvano · Answer

so in problem dirty we have Ah 7 47 that reaches its takeoff speed off one 156. My owes our in just 35.2 seconds. Okay, The problem wants to know what is Thio Average acceleration off the problem off the airline. And we know that average acceleration is determined by the velocity divided by the time. The only problem is our velocity is in miles per hour. We need took over two meters per second. There is a way to do this. Let&#x27;s see, we can just for miles per hour, four meters per second. We just need to divide by 2.2 three seven. So we have one 56 divided by two points to 37 This is something around 17 medias or second. So our final answer it&#x27;s going to be acceleration. It goes to 70 meters per second, divided by 35.2. This is equal to two meters per second square. That&#x27;s the final answer for this question. Things were watching

Sheh Lit Chang · Answer

in this question. We want to find the average acceleration and average speed off the dragster. Okay, so every acceleration a the formula is that TV over the team. You put the given number Sitges Tree tree 2.75 No, it&#x27;s good. All right. Bye. 4.477 seconds. You get 74 point tree too. Mom was our give up by seconds. Okay. And to calculate average speed, uh, first, we convert 4.477 seconds in two hours, which is to do the conversion be Do it by 60 to convert into how many minutes and you do it by 60 again to come to final the amount of hours. Okay, so the unit you use a calculator, you get 1.24 times 10 to the minus three. Okay, then the average feet, the formula is distance. You have the time put in there given information, which is your 0.25 miles. You are by 1.24 times 10 to the ministry. Our you get 2201 mom&#x27;s car. Okay, So the answers are if this is the average speed, and then is this the average acceleration

Robert Zaballa · Answer

in this problem. We want to know what the amount of time was in accelerating to the takeoff speed. Given that that speed was 320 kilometers per hour and the mean acceleration was 2.9 meters per second squared. So I&#x27;ve written that is the final speed. But we also need to know what the initial speed Waas. But we can already make one observation that will tell us that the plane had to be at rest initially. So the initial speed was simply zero. So we simply right v I is equal to zero kilometers per hour and after that we can use the equation that the mean acceleration is equal. Teoh the difference in velocities. I refer to these A speeds but really we can also just in one dimension in this case, call these velocities for this problem. Ah, this mean acceleration is the difference in velocities over the time interval that the velocity changes. So we&#x27;re gonna find this time interval and to do so, we can invert this equation. So if we multiply both sides of the mean acceleration times the time interval, then it will cancel on the right side and we can also divide by the mean acceleration on both sides. It&#x27;ll cancel on the left side and we&#x27;re left with the equation for the time interval. That&#x27;s the equation will use. The only thing we need to do now is convert the final velocity two meters per second. Since the acceleration is in meters per second squared. So we already have kilometers and we can convert that two meters first. Then we&#x27;ll convert hours two seconds. So let&#x27;s start with 320 kilometers per hour. And if I write one kilometer down here, this is equivalent to 1000 meters. If I write one hour appear, this is equivalent to 60 minutes and if I write one minute up here, this is equivalent to 60 seconds. So this is equal to 320. Well, we&#x27;ll continue with that shortly. I&#x27;m just gonna illustrate how this method will cancel the units properly. So kilometer will cancel here. Um, meters will stay, ours will cancel, minutes will cancel and seconds will stay. So now we have 320 times 1000 with the meter unit remaining divided by 60 times 60 with the second unit remaining. So now we&#x27;re in meters per second and when you carry out this calculation you obtained 320 over 3.6 meters per second, which is equal to you, 88 0.89 meters per second. So now that we have VF and we know that b I zero, we can go ahead and get Delta T. So I&#x27;ll just draw a line here to separate. Delta T is equal to 88 0.89 minus zero, divided by 2.9 and this is equal to 30.65 seconds and that&#x27;s the amount of time needed to accelerate.

Wesley Hines · Answer

so average acceleration is equal to the displacement philosophy over the displacement of time. So the displacement of velocity has been equal to be a the final distributed. I just be initial time. Now we know that the final velocity is 35 meters per second and we know that the initial velocity is zero as it started from rest, meaning it wasn&#x27;t moved and this took it a total of eight seconds. So I&#x27;m here. Begin to solve the acceleration by plugging in. This will give 35/8, which gives an acceleration equal to four wait 375 meters per second squared.

Matt Just · Answer

Okay, so we know that the acceleration of this rocket is twenty meters per second. Squared someone right? That is he squared h over DT squared equals twenty meters per second squared or H is thie height above the ground and then t is the time to This isn&#x27;t meters in the time after lunch, which is in seconds here. Okay? And we know that the second derivative evaluated in Syria. So this is the initial velocity. So danged titties velocity when t zero. So before the engines fire and the rocket starts accelerating, the velocity is zero. Okay. And yes, I know the D H d T is going to be an anti derivative of twenties a twenty wass seeing, but because of the lost year zero and tia zero, if I plug in t equals zero, actually get this sea of zero. So the d h d t. Really, it&#x27;s just twenty. And so what? I want to know. I want to know how fast the rocket will be going. One minute later, Silent D H gt evaluated at one minute, which is sixty seconds out. Care focus. Tea is actually in seconds, and this is equal to twenty times sixty, which is two hundred, and this will be in meters per second

Problem

Jules Verne In his novel From the Earth to the Mo…

Problem 49 Easy Difficulty

The Detonator On a ride called the Detonator at Worlds of Fun in
Kansas City, passengers accelerate straight downward from rest to
45 $\mathrm{mi} / \mathrm{h}$ in 2.2 seconds. What is the average acceleration of the
passengers on this ride?

Answer

73636.36 $\mathrm{mi} / \mathrm{h}^{2}$

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