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The Detonator On a ride called the Detonator at Worlds of Fun inKansas City, passengers accelerate straight downward from rest to45 $\mathrm{mi} / \mathrm{h}$ in 2.2 seconds. What is the average acceleration of thepassengers on this ride?

73636.36 $\mathrm{mi} / \mathrm{h}^{2}$

Physics 101 Mechanics

Chapter 2

One-Dimensional Kinematics

Motion Along a Straight Line

Rutgers, The State University of New Jersey

Hope College

University of Sheffield

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So in this question we have the passengers over right, accelerating downwards from rests to a velocity to a speed. The finest front of velocity of 45. My owes for our in a time of just 2.2 seconds. And the problem wants to know what is the average acceleration off the off the right, Let's see average acceleration. We know that the average acceleration is just the difference. And the loss. It's divided by the total time we spent to just fridges velocity. We know that the velocity is just 45 miles Pereira because the initial velocity zero So what is the time? Well, our time right now isn't seconds. So we need to change the time for hours. So how do we change the time off seconds from ours? We know that transforming seconds two minutes is just divided by 60 and transforming minutes. Two hours was just dividing by 60. So divided by 60 again, we just I have two divided this 2.2 divided by tree 1006 100. This is going to be something around 6.1111 times 10 to the power off minors. For now, we can calculate it. Our average acceleration the average acceleration is going to be 45 divided by 6.1111 time staying to the power of minus for this power goes up. So we have the average acceleration. Both seven point 36 36 Theiss times 10 to the power of four or right average acceleration plus seven, 3636 My owes for our That's the final answer. Thanks for watching.

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