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Question 16.
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The diagram below shows the currents through the branches of an electric circuit.
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We are to determine the amount of current that is being red or the current that flows through the amateur a here.
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To help us answer the question, we will apply kirchof's junction rule, which tells us that at any junction, the summation of the current is zero.
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Taking the algebraic sign of the current as positive if it's going into the junction and negative if it's going away from the junction.
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So let's take a look and analyze our circuit here.
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In the upper branch, we have two currents that are going into the junction.
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So let's label junction, the upper junction as a and then another junction as b.
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So at junction a, we have a summation of current here that is equivalent to 0.
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So we have positive 10 amps, positive 5 amps, plus the unknown in this branch, vertical branch here, let's just call it as i or i sub 1 is equal to 0.
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Hence, i sub 1 here is given as negative 15 amps.
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So the negative sign here tells us that, of course, these 15 amps is going away from junction a.
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So we now know that there's a 15 amp current going in the vertical branch here.
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Therefore, this 15 amp will now go to junction b...