00:01
So in this problem, we are given a diagram which represents a reaction mixture and the reaction here, which is going on, is a 2 in gaseous condition, reacting with 2b, which is also in gaseous condition, and they are in equilibrium with 2ab, which is also gas.
00:24
Now, in first part of this question, we have to calculate the equilibrium constant case c for the reaction.
00:32
The volume is given as 2 liter and we have to find out the value of case c.
00:40
So first you have to write down the expression for the case here, the equilibrium constant for this reaction.
00:46
So the expression for case will be the product concentration over the reactant concentration.
00:54
And since we have 2 heavy, 2 will go as a power here.
00:57
And in the denominator, we will have the reactant concentration, a2, and b whole power two since you have two b so this is the expression for kc for this reaction now we have to know the concentration for each of the product and reactant so so to find the concentration concentration is basically the number of moles over volume so we know the volume here but we have to know the number of moles so if we assume that each of the molecules given here as one mole so we can see that from here if we assume the red ones as a 2 so we have 2 a 2 and if we consider the blue ones as b we have 2b and we have ab is this red and blue mixture one so we have 1 2 3 4 of ab so first we calculate the number of moles for ab so so since we have 4 ab, that means number of more for ab will be 4 mole...
