The difference in the standard free energies of formation for 1 -butene and 2 -methylpropene is $13.4 \mathrm{~kJ} \mathrm{~mol}^{-1}$ (3.2 kcal mol $^{-1}$ ). (See the previous problem for a definition of $\Delta G_{\mathrm{f}}^{\mathrm{o}}$ )
(a) Which compound is more stable? Why?
(b) The standard free energy of activation for the hydration of 2 -methylpropene is $22.8 \mathrm{~kJ} \mathrm{~mol}^{-1}\left(5.5 \mathrm{kcal} \mathrm{mol}^{-1}\right)$ less
than that for the hydration of 1 -butene. Which hydration reaction is faster?
(c) Draw reaction free-energy diagrams on the same scale for the hydration reactions of these two alkenes, showing the relative free energies of both starting materials and rate-determining transition states.
(d) What is the difference in the standard free energies of the transition states for the two hydration reactions? Which transition state has lower energy? Using the mechanism of the reaction, suggest why it is more stable.