00:01
For this problem on the topic of diffraction and polarization, we are given the equation that describes the diffraction pattern of a single slit with beta equal to 2 pi a sign theta over lambda, and the central maximum at beta equal to 0, and the side maximum approximately at beta over 2 equal to m plus a half times pi for m is equal to any positive integer.
00:27
We want to find the location of the first side maximum, where m is equal to 1, and then the location of the second side maximum.
00:36
Now we have the equation i is equal to i max times the sign of beta over 2 divided by beta over 2 all squared.
00:52
We want to find the i d beta and let that equal to 0.
00:56
So the derivative of i with respect to beta is equal to i max into 2 sine beta over 2 divided by beta over 2 into beta over 2 times the cosine of beta over 2 multiplied by a half minus e sine.
01:32
Of beta over 2 multiplied by a half, and all of this divided by beta over 2 squared.
01:51
Now, if we let this equal to 0, then the possibility sine beta over 2 equal to 0 locates all of the minima and the central maximum.
02:05
According to beta over 2 is equal to 0 times any positive integer multiple of pi, 0, pi, 2 pi, etc...