Question
The displacement of a particle is given by $\mathrm{x}=3 \sin (5 \pi t)+4 \cos (5 \pi t)$ The amplitude of particle is [MP PMT 1999](a) 3(b) 4(c) 5(d) 7
Step 1
Step 1: Given the displacement of a particle is $\mathrm{x}=3 \sin (5 \pi t)+4 \cos (5 \pi t)$, we can write this in the form of $x=A\sin(5\pi t+\phi)$, where $A$ is the amplitude and $\phi$ is the phase difference. Show more…
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