Question
The displacement, s, of a particle is given by$$s=t^{3}-6 t^{2}+12 t$$
Step 1
$$ v = \frac{ds}{dt} = 3t^2 - 12t + 12 $$ Show more…
Show all steps
Your feedback will help us improve your experience
Zulfiqar Ali and 95 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
" The displacement of a particle is represented by the following equation : s = 3t^3 + 7t^2 + 5t + 8 where s is in metres and t in seconds. The acceleration of the particle at t = 1s is :"
The velocity of a particle is $\mathbf{v}=\{3 \mathbf{i}+(6-2 t) \mathbf{j}\} \mathbf{m} / \mathbf{s}$ where $t$ is in seconds. If $\mathbf{r}=\mathbf{0}$ when $t=0,$ determine the displacement of the particle during the time interval $t=1 \mathrm{s}$ to $t=3 \mathrm{s}$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD