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The dissociation energy of the hydrogen molecule (i.e., the energy required to separate the two atoms) is 4.48 eV. In the gas phase (treated as an ideal gas), at what temperature is the average translational kinetic energy of a molecule equal to this energy?

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$3.46 \times 10^{4} \mathrm{K}$

Physics 103

Chapter 29

Atoms, Molecules, and Solids

Atomic Physics

Nuclear Physics

University of Michigan - Ann Arbor

University of Washington

Hope College

McMaster University

Lectures

02:42

Atomic physics is the field of physics that studies atoms as an isolated system of electrons and an atomic nucleus. It is primarily concerned with the arrangement of electrons around the nucleus and the processes by which these arrangements change. The theory of quantum mechanics, a set of mathematical rules that describe the behaviour of matter and its interactions, provides a good model for the description of atomic structure and properties.

02:26

In physics, nuclear physics is the field of physics that studies the constituents and interactions of atomic nuclei. The most commonly known applications of nuclear physics are nuclear power generation and nuclear weapons technology, but the research has provided application in many fields, including those in nuclear medicine and magnetic resonance imaging, ion implantation in materials engineering, and radiocarbon dating in geology and archaeology.

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The dissociation energy of…

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question 32. We want to take the dis association energy of the hydrogen molecules. So when it's gonna go flying apart, essentially sit bond like this, and then we want to see if we have it in the gas. At what temperature is the kinetic energy going to be equal to that dissociation energy? So let's read it out here e d will be our dissociation energy of four point for eight electron volts. And then we're going to be calculating the Connecticut and she which is right. It is key. The simple form for translational kinetic energy. The average is just the postman, constant times the temperature, most of my three halves. So if we want to find the temperature at which the association occurs, so at which point this bond brakes, then we want to sit this equal to this. So then we have e. D is equal to three halfs bolts mons constant time's temperature rearrange through a little bit of algebra to get, um, two. Eat Association over three. Okay, which is bottom. It's constant. Something that we know and then plug in. I mean, retrieve something in Kelvin, which is three point for six times 10 to the four Come in. This is actually quite hot about an order of magnitude hotter than boiling point of water. So you don't have to worry about hydrogen dissociating at a sort of room temperature situation.

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